Discrete time convolution:
$$ (f \ast g)[n] \equiv \sum_{m = -\infty}^{\infty} f[m]g[n-m] $$
Continuous time convolution:
$$ (f \ast g)(t) \equiv \int_{-\infty}^{\infty} f(\tau)g(t - \tau) d\tau $$
$$ f \ast g = g \ast f $$
$$ f \ast (g \ast h) = (f \ast g) \ast h $$
$$ (f + g) \ast x = f \ast x + g \ast x $$